Code & Func

第79天。

Given a string, you need to reverse the order of characters in each word within a sentence while still preserving whitespace and initial word order.

Example 1: Input: “Let’s take LeetCode contest” Output: “s’teL ekat edoCteeL tsetnoc” Note: In the string, each word is separated by single space and there will not be > any extra space in the string.

用python的话就很简单了：

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def reverseWords(self, s):
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    """
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    :type s: str
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    :rtype: str
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    """
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    words = s.split()
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    for i in range(len(words)):
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        words[i] = words[i][::-1]
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    return ' '.join(words)

然后是dicuss中的c解法：

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void reverse(int b, int e, char *s){
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    while(b < e) {
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        s[b] = s[b] ^ s[e];
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        s[e] = s[b] ^ s[e];
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        s[b] = s[b] ^ s[e];
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        b++;
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        e--;
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    }
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}
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char* reverseWords(char* s) {
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    int i, s_len = strlen(s), index = 0;
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    for(i = 0; i <= s_len; i++) {
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        if((s[i] == ' ') || (s[i] == '\0')){
6 collapsed lines
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            reverse(index, i - 1, s);
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            index = i + 1;
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        }
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    }
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    return s;
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}