第68天。

今天的题目是Longest Continuous Increasing Subsequence:

Given an unsorted array of integers, find the length of longest continuous increasing subsequence (subarra y).

Example 1: Input: [1,3,5,4,7] Output: 3 Explanation: The longest continuous increasing subsequence is [1,3,5], its length is 3. Even though [1,3,5,7] is also an increasing subsequence, it’s not a continuous one where 5 and 7 are separated by 4. Example 2: Input: [2,2,2,2,2] Output: 1 Explanation: The longest continuous increasing subsequence is [2], its length is 1. Note: Length of the array will not exceed 10,000.

题目比较简单，只需要遍历一遍所有元素，然后每次都比较它和它前面一个元素的大小即可：

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int findLengthOfLCIS(vector<int>& nums) {
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    if (nums.size() == 0) return 0;
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    int ret = 0;
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    int a = 1;
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    for(int i = 0;i + 1 < nums.size();i++)
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        if (nums[i] < nums[i+1]) a++;
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        else {
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            ret = max(a,ret);
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            a = 1;
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        }
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    return max(a,ret);
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}